(Q4) A 1.5 m tall boy is looking at the top of a temple which is 30 metre in height from a point at certain distance. The angle of elevation from his eye to the top of the crown of the temple increases from 30o to 60o as he walks towards the temple. Find the distance he walked towards the temple.

Solution :

6030templeAd1.5 m1.5 m1.5 mB30 - 1.5 = 28.5m

Height of the temple = 30 m

Height of the man = 1.5 m

Initial distance between the man and temple = d m. say

Let the distance walked = x m.

From the figure

tan ° =
30 - 1.5
d
=
1
√3
=
28.5
d

∴ d = 28.5 × √3 m......(1)

Also tan 60° =
28.5
d - x
=
d - x

(d - x) =

( × √ - x) =

× - √ x =

x = × -

x = × =

∴ x =
=
× 3
= 19√3

=

= m.

∴ Distance walked = m.